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Postings from May 2001
> I'm interested in what happens with interactions:
>
> $a = @b;
>
> Does this:
>
> 1. Get the length (doesn't seem to make sense now)
No. length(@b) or @b.length() for that.
> 2. Pull a reference to @b (like Perl5's "$a = \@b")
Yep. Scalar context eval of arrays, hashes, and subs produces a reference.
> 3. Get the first element of @b
No. That's still:
($a) = @b;
...which may well grab *only* the first element, because the lvalue's
structure determines the rvalue's eval context (just like a sub's
parameter list determines its argument's contexts)
> Similarly, how about:
>
> %c = @d;
>
> Does this:
>
> 1. Create a hash w/ alternating keys/vals like Perl5
> 2. Do the equivalent of "%c = \@d" in Perl5
> 3. Or the mystery meat behind Door #3
This one's still less-than-certain. Definitely either 1 or 3 though.
If option 3, it would be the equivalent of the Perl 5:
%c = map {($_=>undef)} @d;
Damian
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