EX3: $a == $b != NaN

Okay, so this:

    100 < -s $filepath <= 1e6

really means this:

    100 < -s $filepath  &&  -s $filepath <= 1e6

which means that this:

    $a == $b != NaN

really means this:

    $a == $b && $b != NaN

But "$a == $b != NaN" is supposed to "[solve] the problem of numerical
comparisons between non-numeric strings."  Well, what if:

    $a = 'hello';
    $b = 0;

Doesn't that mean:

    "hello" == 0 && 0 != NaN

will evaluate to true?  Is that expected behavior for comparing
"hello" and 0 with the EQ operator?  Or am I not getting the
purpose of the "$a == $b != NaN" idiom?

-John

• EX3: $a == $b != NaN by John Siracusa
• Re: EX3: $a == $b != NaN by Damian Conway
• Re: EX3: $a == $b != NaN by Damian Conway
• Re: EX3: $a == $b != NaN by Bart Lateur
• Re: EX3: $a == $b != NaN by John Siracusa